Hello Spectrum BASIC experts,

I am new to programming and am self-teaching BASIC. I had an idea and would appreciate some mentoring on this. To test a simple game idea I would like to store random numbers in an array. Thank you for any guidance you can spare.

Cheers,

KB

## Spectrum Basic:putting random numbers in an array

- Blerkotron
- Dizzy
**Posts:**89**Joined:**Mon Nov 13, 2017 12:36 pm

### Re: Spectrum Basic:putting random numbers in an array

Try something like this:

Explanations:

10: initialise the random number generator and dimension your array of numbers, a, to hold ten numbers.

20: loop ten times, assigning a random number to each element of the array in turn. The number will be an integer (int) from 1 to 10 (rnd*10). Actually int(rnd*10) gives you a number from 0 to 9, so the +1 prevents you from getting a 0 and allows you to get a 10.

30: loop ten times again, this time printing each of the ten array elements to the screen.

Code: Select all

```
10 randomize: dim a(10)
20 for n = 1 to 10: let a(n) = int(rnd*10)+1: next n
30 for n = 1 to 10: print a(n): next n
```

10: initialise the random number generator and dimension your array of numbers, a, to hold ten numbers.

20: loop ten times, assigning a random number to each element of the array in turn. The number will be an integer (int) from 1 to 10 (rnd*10). Actually int(rnd*10) gives you a number from 0 to 9, so the +1 prevents you from getting a 0 and allows you to get a 10.

30: loop ten times again, this time printing each of the ten array elements to the screen.

1 x

### Re: Spectrum Basic:putting random numbers in an array

You beat me to it @Blerkotron

I had something similar:

I had something similar:

1 x

### Re: Spectrum Basic:putting random numbers in an array

How about we get a little fancier?

Code: Select all

`10 LET a$="0123456789": DIM b(10): FOR f=1 TO 10: LET c=(RND*LEN a$)+1: LET b(f)=VAL a$(c)+1: LET a$=a$( TO c-1)+a$(c+1 TO): NEXT f`

1 x

### Re: Spectrum Basic:putting random numbers in an array

A (more unnecessarily complicated but fun) ZXBasic approach here:

Cheers

Code: Select all

```
REM initialize screen
PAPER 0 : BORDER 0 : INK 7 : CLS
REM initialize array and variables; arrays starts at 0 but it can be changed
DIM myarray(9) as UBYTE
DIM y AS UBYTE
REM loop to fill array several times until user is satisfied with the result
DO
FOR y = 0 TO 9
myarray(y) = (RND*100) REM INT is not needed because the array and variable were initialized as UBYTE
PRINT AT y,0; "myarray("; y; ")= "; myarray(y); " ";
NEXT y
PRINT AT 22,0; INK 5; BOLD 1; "Press ENTER to STOP or"; AT 23,0; INK 6; ITALIC 1;"Press any other key to retry";
PAUSE 0
LOOP WHILE INKEY$ <> CHR(13)
```

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### Re: Spectrum Basic:putting random numbers in an array

Great Gentlemen,

Many helpful folks here, best quality forum I use. I especially appreciate the variations.

Cheers to you all.

And of course now it makes total sense, as most things seem to once you have the answer.

KB

Many helpful folks here, best quality forum I use. I especially appreciate the variations.

Cheers to you all.

And of course now it makes total sense, as most things seem to once you have the answer.

KB

1 x